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- Jun 22, 2012

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*writes the following:*

**(see text below)**" ... ... Each matrix \(\displaystyle A\) in this group determines an invertible linear transformation \(\displaystyle f_A: \mathbb{R} \to \mathbb{R}\) defined by \(\displaystyle f_A(x) = x A^t\) ... ... "

I know that one may define entities how one wishes ... but why does Armstrong define \(\displaystyle f\) in terms of the transpose of \(\displaystyle A\) rather than just simply \(\displaystyle A\) ... there must be some reason or advantage to this ... but what is it? Can someone help to explain ...

I note in passing that Kristopher Tapp in his book, "Matrix Groups for Undergraduates" (Chapter 1, Section 5) ...

*... defines the action of a linear transformation ( multiplication by a matrix \(\displaystyle A\)) as \(\displaystyle R_A = X \cdot A\) ... thus not using the transpose of \(\displaystyle A\) ...*

**see text below**Hope that someone can help ...

Peter

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The above post refers to the start of Ch. 9 of M. A. Armstrong's book, "Groups and Symmetry" ... so I am providing the relevant text ... as follows:

The above post also refers to Chapter 1, Section 5 of Kristopher Tapp's book, "Matrix Groups for Undergraduates" ... so I am providing the relevant text ... as follows:

Note that Tapp uses \(\displaystyle \mathbb{K}\) to refer to one of the real numbers, the complex numbers or the quaternions ...

Hope that helps,

Peter