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fstam2
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Simple Harmonic Oscillation
Hello, I am new here and wish I had found this forum earlier in the semester. Here is the situation:
A block (mass m=0.75 kg) rests on a horizontal surface (frictionless), attached to a horizontal spring (k=235 N/m). At time t=0, the block is located at the equilibrium position (x=0), given a sove that compresses the spring. The block gains a speed of 2.5 m/s instantaneously.
(ii) What is the acceleration of the block at time, t=3.0 s?
The equation I have found that might be correct is:
a= -(kA/m)sin(2(pie)t/T), where t= 3.0s and T=.352 based on
T= 2(pie)sqrt(m/k)
Using this equation I arrived at -35.2 m/s2 (the negative is because of the direction of the acceleration at t= 3.0s). This answer makes sense in that the acceleration has slowed from a max acceleration of 43.8 m/s2.
Any suggestions, advice, criticisms?
Thanks for your help.
Todd
Hello, I am new here and wish I had found this forum earlier in the semester. Here is the situation:
A block (mass m=0.75 kg) rests on a horizontal surface (frictionless), attached to a horizontal spring (k=235 N/m). At time t=0, the block is located at the equilibrium position (x=0), given a sove that compresses the spring. The block gains a speed of 2.5 m/s instantaneously.
(ii) What is the acceleration of the block at time, t=3.0 s?
The equation I have found that might be correct is:
a= -(kA/m)sin(2(pie)t/T), where t= 3.0s and T=.352 based on
T= 2(pie)sqrt(m/k)
Using this equation I arrived at -35.2 m/s2 (the negative is because of the direction of the acceleration at t= 3.0s). This answer makes sense in that the acceleration has slowed from a max acceleration of 43.8 m/s2.
Any suggestions, advice, criticisms?
Thanks for your help.
Todd
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