- #1
Leeoku
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Homework Statement
A m2 = 4.63 kg mass is connected by a light cord to a m1 = 2.10 kg mass on a smooth surface (see the figure below).The pulley rotates about a frictionless axle and has a moment of inertia of 0.513 kg•m2 and a radius of 0.257 m. Assuming that the cord does not slip on the pulley, find the acceleration of m1.
Homework Equations
Torque = I*alpha = F*D
The Attempt at a Solution
FBD Mass 1
F_net = Tension 2... mass1*a = Tension 2
FBD Mass 2
F_net = mg-T1
T1 = mass2*g- mass2*a
Torque = I*alpha
Torque_1+Torque_2 = I*alpha
Tension_1+Tension_2 = I*alpha/r
and now I am stuck. Correct answer is 3.13 m/s^2