- #1
jlmccart03
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Homework Statement
The membrane around a cell normally has layers of charge that create a potential difference between its outer and inner surfaces. This difference is about 72 mV .
When a singly ionized potassium ion moves through a channel in the membrane passing from the outside to the inside, what is the magnitude of the work done by the electric field of the membrane?
Homework Equations
W = F*d
W = V*U
The Attempt at a Solution
So I know that the charge of a K ion is +1 so it is simply 1.6e-19 and converting 72 mV to 0.072 V I can then just multiply both to get the change in work correct? I don't get why that is wrong then.