Right. So what must the normal force be to balance this force plus gravity?Spartan Erik said:Well I imagine the third component could be sin(23.5 degrees) x 100 = 39.875
The magnitude of normal force in a frictionless system is equal to the weight of the object. This is because in a frictionless system, there is no opposing force acting on the object, so the normal force must be equal to the weight of the object in order to maintain equilibrium.
In a frictionless system, the magnitude of normal force remains constant throughout the motion. This is because there is no friction to change the normal force, so it will always be equal to the weight of the object.
Yes, the magnitude of normal force is directly proportional to the mass of the object. This means that as the mass of the object increases, the normal force also increases in order to maintain equilibrium.
The magnitude of normal force is affected by the angle of the surface in a frictionless system. As the angle of the surface increases, the normal force decreases because some of the weight of the object is now acting in a direction perpendicular to the surface.
No, the magnitude of normal force cannot be negative in a frictionless system. This is because the normal force is always acting perpendicular to the surface, so it cannot have a negative value. If there is an opposing force acting on the object, it would be considered a different type of force, such as a tension force or a gravitational force.