- Thread starter
- #1

\[

H_1(s) = \frac{1}{(s + 1)(s + 3)},\qquad \text{Re} \ \{s\} > -1

\]

I have no idea what to do for this. Can someone explain how to do a problem like this?

- Thread starter dwsmith
- Start date

- Thread starter
- #1

\[

H_1(s) = \frac{1}{(s + 1)(s + 3)},\qquad \text{Re} \ \{s\} > -1

\]

I have no idea what to do for this. Can someone explain how to do a problem like this?

- Feb 13, 2012

- 1,704

In case of highpass or band pass is $\displaystyle H_{1} (0) = 0$ and that isn't verified in this case. The only possible alternative is then...

\[

H_1(s) = \frac{1}{(s + 1)(s + 3)},\qquad \text{Re} \ \{s\} > -1

\]

I have no idea what to do for this. Can someone explain how to do a problem like this?

Kind regards

$\chi$ $\sigma$

- Admin
- #3

- Mar 5, 2012

- 8,876

The standard way to analyze such a function is a Bode plot.

\[

H_1(s) = \frac{1}{(s + 1)(s + 3)},\qquad \text{Re} \ \{s\} > -1

\]

I have no idea what to do for this. Can someone explain how to do a problem like this?

It will tell you what type of filter it is and also what its characteristics are.

More specifically, a low pass filter has high H(0) and goes down when s increases.

A high pass filter has low H(0) and increases with s.

A band filter first increases from s=0 and up and then decreases again.

- Thread starter
- #4

Can you provide an example transfer function for a bandpass?The standard way to analyze such a function is a Bode plot.

It will tell you what type of filter it is and also what its characteristics are.

More specifically, a low pass filter has high H(0) and goes down when s increases.

A high pass filter has low H(0) and increases with s.

An band filter first increases from s=0 and up and then decreases again.

- Admin
- #5

- Mar 5, 2012

- 8,876

For instanceCan you provide an example transfer function for a bandpass?

$$H(s) = \frac{s}{(s-1)(s-100)}$$

bodeplot s/((s-1)(s-100)) - Wolfram|Alpha Results

- Thread starter
- #6

So if the numerator was \(s^2\), we would have highpass correct?

- Admin
- #7

- Mar 5, 2012

- 8,876

Yes.So if the numerator was \(s^2\), we would have highpass correct?