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science_rules
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Homework Statement
A baseball is thrown. The ball leaves your hand with a velocity of 15 m/s at 60 degrees above the horizontal. acceleration due to gravity is 9.8 m/s^2. Determine the velocity (magnitude and direction) of ball at the maximum height.
Homework Equations
im not sure, but i think I am supposed to find the x and y components of the velocity first:
V_x = Voxcos60 = 15 cos 60 = 7.5 m/s
V_y = Voysin60 = 0 sin 60 = 0
does this mean that the velocity at max height is just the horizontal velocity component? i know with a horizontal projectile motinon problem, you have to find the components and then plug them into this equation: V^2 = Vx^2 + Vy^2 and then use tan theta to find theta for the direction, but I am not sure if this applies to a projectile motion problem which involves an angle.
The Attempt at a Solution
see above