Magnetic hysteresis loop area meaning

[EmilyRuck]

Let's consider the Magnetic hysteresis loop of a certain material: https://www.nde-ed.org/EducationResources/CommunityCollege/MagParticle/Physics/HysteresisLoop.htm is an example. In many sites and books it is written that its area is proportional to the energy wasted as heat, so [itex]A = kE_d[/itex].
In particular, that area "is related to the amount of energy dissipation upon reversal of the field" (this is the source). I would like to ask some clarifications:

1) When exactly is that energy dissipated? When the impressed magnetic field [itex]\mathbf{H}[/itex] decreases from the saturation point or when [itex]\mathbf{H}[/itex] increases till the saturation point?
2) How can be circuitally represented that energy dissipation in the circuit of a transformer like this?
3) Maybe [itex]E_d[/itex] can be obtained as an integral. If [itex]A = kE_d[/itex], what are the steps needed to mathematically show this result and which is the meaning of [itex]k[/itex]? (If a link is more convenient than directly typing the steps, it would be excellent as well)
I can't see how dimensionally can be obtained an energy quantity (Joule) from A/m ([itex]\mathbf{H}[/itex]) and from Tesla ([itex]\mathbf{B}[/itex]).

 

[Hesch]

Magnetic energy density ( E_d ) = ½*B*H [ J/m³ ]. So E_d = 0 in b, c, e, f in the attached figure and has a max value i a, d.

If the area of the hysterisis curve = 0, no energy will be dissipated as per cycle.

Units: B*H = [N/(Am)] * [ A/m ] = [ N/m² ] = Nm/m³ = [ J/m³ ]

 

[EmilyRuck]

Thank you!