First of all, how did you get 9 A? Is that what you get for the current through the inductor ? (Yes, I assume you're getting this while the switch is still closed.) ... but how did you get that?utkarshakash said:
SammyS said:
utkarshakash said:
An LR circuit is a type of electrical circuit that contains a combination of inductance (L) and resistance (R) elements.
An open switch is a break in the circuit that prevents current from flowing through the circuit.
To find the current (i) in an LR circuit when the switch is opened, you can use the equation i = I0e-t/τ, where I0 is the initial current, t is the time since the switch was opened, and τ is the time constant of the circuit.
The time constant (τ) of an LR circuit is a measure of how quickly the current in the circuit changes. It is equal to the ratio of the inductance (L) and resistance (R) in the circuit, or τ = L/R.
Analyzing an LR circuit when the switch is opened allows us to understand how the current in the circuit changes over time. This information is useful for designing and troubleshooting electrical circuits, as well as understanding the behavior of inductors and resistors in a circuit.
