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- Jan 26, 2012

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That's not the equation you should solve.I already solved part of the equation, I'm just not sure what to do once I get to

= x^{2}+3x-1/4=0

When I solve using the quadratic equation after this I end up with:

-3 +/- 2squareroot2/2

$\displaystyle \log_4(x)-\log_4(x+3)=-1$. Using MarkFL's suggestion we simplify this to \(\displaystyle \log_{4}\left( \frac{x}{x+3} \right)=-1\). Using the definition of a logarithm this becomes \(\displaystyle 4^{-1}=\frac{x}{x+3}\).

Can you finish from here?

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Here you can simplify a few ways. Maybe you're familiar with the idea of cross-multiplication of fractions.

\(\displaystyle 1(x+3)=4x\) or simply \(\displaystyle x+3=4x\)

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