- Thread starter
- #1
Albert
Well-known member
- Jan 25, 2013
- 1,225
$\pi\approx3.1416$
$A=\dfrac{1}{log_5 19}+\dfrac{2}{log_3 19}+\dfrac{3}{log_2 19}$
$B=\dfrac{1}{log_2\pi}+\dfrac{1}{log_3\pi}$
edit :$B=\dfrac{1}{log_2\pi}+\dfrac{1}{log_{\color{red}5}\pi}$
$Prove: \,\, A < B$
$A=\dfrac{1}{log_5 19}+\dfrac{2}{log_3 19}+\dfrac{3}{log_2 19}$
$B=\dfrac{1}{log_2\pi}+\dfrac{1}{log_3\pi}$
edit :$B=\dfrac{1}{log_2\pi}+\dfrac{1}{log_{\color{red}5}\pi}$
$Prove: \,\, A < B$
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