Linear transformations with functions

[Xyius]

For the linear transformation,

[tex]T: R^2\rightarrow R^2, T(x,y) = (x^2,y)[/tex]

find the preimage of..
[tex]f(x)= 2x+1[/tex]

I have no trouble with these types of problems when it comes to vectors that aren't functions. Any help would be appreciated! Thanks!

~Matt

 

[radou]

This is no linear transformation, since T(α v) = T(α(x, y)) = T(αx, αy) = (α^2x^2, αy), which does not equal αT(v), for some v from R^2 and some α from R.

 

[HallsofIvy]

For the linear transformation,

[tex]T: R^2\rightarrow R^2, T(x,y) = (x^2,y)[/tex]

find the preimage of..
[tex]f(x)= 2x+1[/tex]

I have no trouble with these types of problems when it comes to vectors that aren't functions. Any help would be appreciated! Thanks!

~Matt

Since T is mapping pairs of numbers into pairs of numbers, I assume that by "f(x)= 2x+1" you mean the set of pairs (x, 2x+1)[/math]

So you are looking for (x, y) such that [itex]T(x, y)= (x^2, y)= (a, 2a+1)[/itex] for some number a. Okay, since [itex]x^2= a[/itex], x can be either [itex]\sqrt{a}[/itex] or [itex]-\sqrt{a}[/itex]. And, of course, y= 2a+ 1. That is, the preimage is the set in [itex]R^2[/itex] [itex]\{(x,y)| y= 2\sqrt{x}+ 1 or y= -2\sqrt{x}+ 1\}[/itex].