- #1
Silversonic
- 130
- 1
Homework Statement
Consider two normalised, orthogonal solutions of the TDSE
(Note all my h's here are meant to be h-bar, I'm not sure how to get a bar through them).
[itex]\Psi_1 = \psi_1 (x) e^{-E_1 it/h}[/itex]
[itex]\Psi_2 = \psi_2 (x) e^{-E_2 it/h}[/itex]
Consider the wavefunction
[itex] \Phi = \sqrt{\frac{1}{3}}\Psi_1 + \sqrt{\frac{2}{3}}\Psi_2 [/itex]
Which is also a normalised solution to the TDSE. Any linear superposition of solutions to the TDSE is also a solution.
Homework Equations
The TDSE is;
[itex]\widehat{H}\Phi = ih\frac{\delta}{\delta t}\Phi[/itex]
The Attempt at a Solution
This isn't a question, I've just gone to pursue the statement that the linear superposition is also a solution. I can't see to show it though.
Using [itex] \Phi = \sqrt{\frac{1}{3}}\Psi_1 + \sqrt{\frac{2}{3}}\Psi_2 [/itex]
[itex]\widehat{H}\Phi = ih\frac{\delta}{\delta t}\Phi = \sqrt{\frac{1}{3}}E_1\psi_1 (x) e^{-E_1 it/h} + \sqrt{\frac{2}{3}}E_2\psi_2 (x) e^{-E_2 it/h}[/itex]
Which I cannot manage to get into the form
[itex] (\sqrt{\frac{1}{3}}E_1 + \sqrt{\frac{2}{3}}E_2)\Phi [/itex]
Which is the form is should be in if it was a solution surely?