Linear motion with variable forces

[jiayingsim123]

Homework Statement

A racing car of mass 20000kg accelerates with a driving force of 480(t-10)^2 Newtons until it reaches its maximum speed after 10 seconds. Find its maximum speed, and the distance it travels in reaching this speed.

The Attempt at a Solution

Again, I can't seem to get the distance traveled after the second integration.
m=2000kg
F=480(t-10)^2
a=F/m
= 6(t-10)^2/25
v=∫a dt
=[6(t-10)^3/3]/25 + k
Since t=0, v=0 and therefore v=[6(t-10)^3/3]/25
Vmax is found out to be 80m/s

But integration of v did not give me the answer stated, which is 600m. I got 200m instead.

Please include detailed explanations along with the solution. Thanks! :D

 

[azizlwl]

Homework Statement

A racing car of mass 20000kg accelerates with a driving force of 480(t-10)^2 Newtons until it reaches its maximum speed after 10 seconds. Find its maximum speed, and the distance it travels in reaching this speed.

The Attempt at a Solution

Again, I can't seem to get the distance traveled after the second integration.
m=2000kg
F=480(t-10)^2
a=F/m
= 6(t-10)^2/25
v=∫a dt
=[6(t-10)^3/3]/25 + k
Since t=0, v=0 and therefore v=[6(t-10)^3/3]/25
Vmax is found out to be 80m/s

But integration of v did not give me the answer stated, which is 600m. I got 200m instead.

Please include detailed explanations along with the solution. Thanks! :D

What is the mass?

 

[jiayingsim123]

Sorry the mass is 2000kg. :)

 

[azizlwl]

For the velocity you can also use F=dp/dt
[itex]\int_0^t \! f(t) \, \mathrm{d} t. =\int_0^v \! f(mv) \, \mathrm{d} v.[/itex]

Just find v from acceleration by integral
Then find d from v by integral too.

 

[ehild]

a=F/m
= 6(t-10)^2/25
v=∫a dt
=[6(t-10)^3/3]/25 + k
Since t=0, v=0 and therefore v=[6(t-10)^3/3]/25

Your initial velocity is -80 instead of zero. Choose other value for k.

ehild