- #1
maniacp08
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Bored, a boy shoots his pellet gun at a piece of cheese that sits, keeping cool for dinner guests, on a massive block of ice. On one particular shot, his 1.1 g pellet gets stuck in the cheese, causing it to slide 25 cm before coming to a stop. If the muzzle velocity of the gun is 76 m/s and the cheese has a mass of 136 g, what is the coefficient of friction between the cheese and ice?
Relevant equations:
Momentum = Mass * Velocity
This would be an example of an inelastic collision where the two objects stick together.
The KE is not conserved.
I converted the mass of the pellet and the cheese to kg.
Mass of pellet = .0011kg
Mass of cheese = .136kg
Momentum of the pellet = .0011kg * 76m/s = .0836 kg m/s
The momentum will be conserved because there is no external forces.
This is as far as I got, can someone tell me how should I approach this next?
Thanks.
Relevant equations:
Momentum = Mass * Velocity
This would be an example of an inelastic collision where the two objects stick together.
The KE is not conserved.
I converted the mass of the pellet and the cheese to kg.
Mass of pellet = .0011kg
Mass of cheese = .136kg
Momentum of the pellet = .0011kg * 76m/s = .0836 kg m/s
The momentum will be conserved because there is no external forces.
This is as far as I got, can someone tell me how should I approach this next?
Thanks.