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abhishekdas
New member
- Feb 17, 2014
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1/5(1/3x-5)=1/3(3-1/x)
Besides, the notation 1/3x is somewhat ambiguous: it may mean either (1/3)x or 1/(3x). The same pertains to coefficients 1/5 and 1/3: it is recommended to write (1/5) if this number is followed by multiplication. Note that if 1/3x means (1/3)x, then the equation is not linear. So please clarify what you mean by inserting parentheses.1/5(1/3x-5)=1/3(3-1/x)
Since you titled this "linear equations" I would have assumed that your "1/3x" mean "(1/3)x"- that is, "one third times x" rather than 1/(3x), 1 divided by 3x. But then your "1/x" confuses me. From that I have to conclude that this is NOT, as it stands, a "linear equation" and you intend [tex]\frac{1}{5}\frac{1}{3x- 5}= \frac{1}{3}\left(3- \frac{1}{x}\right)[/tex].1/5(1/3x-5)=1/3(3-1/x)
If you have no further questions, then it is a good idea to mark the thread as solved. Otherwise, please post your questions. The thing is that contrary to what some people may think, bare formulas almost never constitute a piece of mathematical work. They must be accompanied by plain text explanations saying what we want to do with such formulas (e.g., solve an equation or find a counterexample), whether a given formula is an assumption or something to prove, what the difficulty of the problem is, why should one consider such problem interesting and so on.1/(15x) -1=1- 1/(3x)
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6/15x =2
What happened here is that help was given by Tennisgoalie to the OP. Admittedly, this would perhaps have been more clear had the post looked more like:If you have no further questions, then it is a good idea to mark the thread as solved. Otherwise, please post your questions. The thing is that contrary to what some people may think, bare formulas almost never constitute a piece of mathematical work. They must be accompanied by plain text explanations saying what we want to do with such formulas (e.g., solve an equation or find a counterexample), whether a given formula is an assumption or something to prove, what the difficulty of the problem is, why should one consider such problem interesting and so on.1/(15x) -1=1- 1/(3x)
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6/15x =2
However, Tennisgoalie just joined MHB within the last 24 hours and may be new to math help sites in general and inexperienced with how to most effectively provide help to others, such as to use plain text to elucidate the steps taken.Assuming the equation is to be interpreted as follows:1/5(1/3x-5)=1/3(3-1/x)
(1/5)(1/(3x) - 5) = (1/3)(3 - 1/x)
then distribution on both sides yields:
1/(15x) -1 = 1 - 1/(3x)
Multiplying 1/(3x) by 5/5 to get 5/(15x), we may then add 1 + 5/(15x) to both sides to obtain:
6/(15x) = 2
Can you continue?