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#### abhishekdas

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- Feb 17, 2014

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1/5(1/3x-5)=1/3(3-1/x)

- Thread starter abhishekdas
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- Feb 17, 2014

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1/5(1/3x-5)=1/3(3-1/x)

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- Jan 26, 2012

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I'm assuming you're trying to solve this equation. What have you tried? Where are you stuck?

- Jan 30, 2012

- 2,575

Besides, the notation 1/3x is somewhat ambiguous: it may mean either (1/3)x or 1/(3x). The same pertains to coefficients 1/5 and 1/3: it is recommended to write (1/5) if this number is followed by multiplication. Note that if 1/3x means (1/3)x, then the equation is not linear. So please clarify what you mean by inserting parentheses.1/5(1/3x-5)=1/3(3-1/x)

- Jan 29, 2012

- 1,151

Since you titled this "linear equations" I would have assumed that your "1/3x" mean "(1/3)x"- that is, "one third times x" rather than 1/(3x), 1 divided by 3x. But then your "1/x" confuses me. From that I have to conclude that this is NOT, as it stands, a "linear equation" and you intend [tex]\frac{1}{5}\frac{1}{3x- 5}= \frac{1}{3}\left(3- \frac{1}{x}\right)[/tex].1/5(1/3x-5)=1/3(3-1/x)

The simplest way to handle problems like this is to get rid of all those fractions by multiplying both sides by the "least common denominator". Since there are no "duplicates" here, the "least common denominator" is just the product of all of the denominators (5)(3x- 4)(3)(x). Multiplying on both side by that will cancel the denominators "5" and "3x - 5" on the left and the denominators "3" and "x" on the right leaving 3x= 5(3x- 5)(3x- 1) which still is not linear- it is the quadratic equation [tex]3x= 45x^2- 60x+ 25[/tex] or [tex]45x^2- 63x+ 25= 0[/tex]. But that equation has

- Feb 23, 2014

- 4

1/(15x) -1=1- 1/(3x)

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6/15x =2

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6/15x =2

- Jan 30, 2012

- 2,575

If you have no further questions, then it is a good idea to mark the thread as solved. Otherwise, please post your questions. The thing is that contrary to what some people may think, bare formulas almost never constitute a piece of mathematical work. They must be accompanied by plain text explanations saying what we want to do with such formulas (e.g., solve an equation or find a counterexample), whether a given formula is an assumption or something to prove, what the difficulty of the problem is, why should one consider such problem interesting and so on.1/(15x) -1=1- 1/(3x)

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6/15x =2

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What happened here is that help was given byIf you have no further questions, then it is a good idea to mark the thread as solved. Otherwise, please post your questions. The thing is that contrary to what some people may think, bare formulas almost never constitute a piece of mathematical work. They must be accompanied by plain text explanations saying what we want to do with such formulas (e.g., solve an equation or find a counterexample), whether a given formula is an assumption or something to prove, what the difficulty of the problem is, why should one consider such problem interesting and so on.1/(15x) -1=1- 1/(3x)

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6/15x =2

However,Assuming the equation is to be interpreted as follows:1/5(1/3x-5)=1/3(3-1/x)

(1/5)(1/(3x) - 5) = (1/3)(3 - 1/x)

then distribution on both sides yields:

1/(15x) -1 = 1 - 1/(3x)

Multiplying 1/(3x) by 5/5 to get 5/(15x), we may then add 1 + 5/(15x) to both sides to obtain:

6/(15x) = 2

Can you continue?

- Jan 30, 2012

- 2,575

Ah, sorry, I should have checked the usernames. Thanks to Tennisgoalie for the help.