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linear approximation

jaredjjj

New member
Jun 3, 2020
5
Have I solved this linear approximation question correctly?
Qqq6.JPG
 

skeeter

Well-known member
MHB Math Helper
Mar 1, 2012
658
yes, $f(2.8) \approx -2.8$

now, how to determine if that value is an over or under estimate?
 

jaredjjj

New member
Jun 3, 2020
5
yes, $f(2.8) \approx -2.8$

now, how to determine if that value is an over or under estimate?
To answer the second half do I have to use the formula f'(x)=sqrt(x^2+7) which would mean -2.8 would be approximately equal to 3.852 which is the same as 2.8.
 

skeeter

Well-known member
MHB Math Helper
Mar 1, 2012
658
To answer the second half do I have to use the formula f'(x)=sqrt(x^2+7) which would mean -2.8 would be approximately equal to 3.852 which is the same as 2.8.
???

The linear approximation is a line tangent to $f(x)$ at the point $(3,-2)$.

What does the sign of $f''(3)$ tell you about the behavior of $f(x)$ at $x=3$ ?