- #1
mozartkart
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Homework Statement
a uniform stick with a mass of 1.00 kg and length of 1.00m has a fixed hinge at one end. It is released at an angel of 60 degrees above the horizontal and it drops with normal gravity. What is the magnitude of the linear acceleration of the point at the free end just after release? express the result as a percentage of g (gravity)
The Attempt at a Solution
attempt
T=r*F*sin(60) T=Inertia*alpha =(mr2)*(a/r)=mra
mra=r*m*g*sin(60)
a=g*sin(60)
Is this a correct method to approach this question with or do I have to use the inertia equation for a rod rotating about one end which is 1/3 *m*L2 ? If that's the case then would this be right?
(1/3*m*L2)*a/r=rmgsin(60)
a=(r2*g*3*sin(60)) / L