- Thread starter
- #1
Alexmahone
Active member
- Jan 26, 2012
- 268
Find $\displaystyle\lim_{n\to\infty}\frac{\sqrt[n]{n}}{\sqrt[n+1]{n+1}}$.
So are you saying that the answer is $\displaystyle\frac{1}{1}=1$?$\sqrt[n]{n}=e^{\frac{\ln n}{n}}$ and $\frac{\ln n}{n}\to 0$ as $n\to\infty$.
Do you know this limitFind $\displaystyle\lim_{n\to\infty}\frac{\sqrt[n]{n}}{\sqrt[n+1]{n+1}}$.
Do you know this limit
$\displaystyle\lim _{u \to \infty } \sqrt{u}=~?$
What is the answer to the OP?It's 1.
$\displaystyle\frac{1}{1}=1$What is the answer to the OP?