# Limit calculation

#### Yankel

##### Active member
Hello

I need some help with this limit. I know I should use the L'hopital rule, but not sure how to do it...any help will be appreciated !

$$\lim_{x\to 0^{+}}x^{3}\cdot (ln(x))^{2}$$

#### MarkFL

I notice this is the indeterminate form $0\cdot\infty$, so I would recommend writing it as:
$\displaystyle \lim_{x\to0^{+}}\frac{\ln^2(x)}{x^{-3}}$
Now we have the indeterminate form $\dfrac{\infty}{\infty}$ and we may apply L'Hôpital's rule.