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When 2 variables x,y are related by y=1+xlogy, find lim(x->1) dy/dx.

So,my first step is differentiating both sides:

dy/dx = logy + x*(1/y)*(dy/dx)

dy/dx = (y*logy)/(y - x)

So, lim(x->1) dy/dx = lim(x->1) (y*logy)/(y - x) = y*logy/(y-1)

Did I get the limit right? So how to draw the graph?