- #1
Physicsit
So here is the problem
Two cylindrical rods, one copper and the other iron, are identical in lengths and cross-sectional areas. They are joined, end-to-end, to form one long rod. A 12-V battery is connected across the free ends of the copper-iron rod. What is the voltage between the ends of the copper rod?
I know that R = resistivity(L/A)
so what I did was created a ratio to get the resistance of the new rod
Riron/Rcopper = (resistivty of iron * L/A)/(resistivty of copper * L/A) = (resistivty of iron)/(resistivty of copper) = 9.7*10^-8/1.72*10^-8
= a resistance of 5.64
I believe that is the resistance of the copper and iron rod connected to each other however I do not know how it helps if it does at all
Two cylindrical rods, one copper and the other iron, are identical in lengths and cross-sectional areas. They are joined, end-to-end, to form one long rod. A 12-V battery is connected across the free ends of the copper-iron rod. What is the voltage between the ends of the copper rod?
I know that R = resistivity(L/A)
so what I did was created a ratio to get the resistance of the new rod
Riron/Rcopper = (resistivty of iron * L/A)/(resistivty of copper * L/A) = (resistivty of iron)/(resistivty of copper) = 9.7*10^-8/1.72*10^-8
= a resistance of 5.64
I believe that is the resistance of the copper and iron rod connected to each other however I do not know how it helps if it does at all