Welcome to our community

Be a part of something great, join today!

Law of Tangent Ignored

  • Thread starter
  • Banned
  • #1

xyz_1965

Member
Jul 26, 2020
81
The next chapter in my personal studies is Law of Sines and Law of Cosines. I am not there yet. I know there is a Law of Tangent but it is rarely used and never taught in a typical trig course anywhere. Why is the Law of Tangent ignored?
 

Country Boy

Well-known member
MHB Math Helper
Jan 30, 2018
426
The "law of tangents" (I had to look it up) says that
"if a is the side of a triangle opposite angle α and b is the side of a triangle opposite angle β then (a-b)/(a+b)=(tan(1/2(α-β)))/(tan(1/2(α+β)))".

You are right- that is not very often taught. I suspect that is because it is much more complicated, especially the dependence on half angles, than either the sine or cosine laws and that it can be replace by those laws.
 
Last edited:
  • Thread starter
  • Banned
  • #3

xyz_1965

Member
Jul 26, 2020
81
The "law of tangents" (I had to look it up) says that
"if a is the side of a triangle opposite angle α and b is the side of a triangle opposite angle β then (a-b)/(a+b)=(tan(1/2(α-β)))/(tan(1/2(α+β)))".

You are right- that is not very often taught. I suspect that is because it is much more complicated, especially the dependence on half angles, than either the sine or cosine laws and that it can be replace by those laws.
Someone deleted 3 or 4 threads I posted about 2 days ago. The reason given was NO WORK SHOWN. I can only show work if I know how to start the solution of the problem.

All I needed was a simple hint or step to get me started. The questions did not need to be deleted. Again, there are questions in my precalculus textbook for which the author dooes not provide samples.

I agree that the Law of Tangent is not needed if the other two solve the problem. Be that as it may, it looks interesting. Can you solve a problem using the Law of Tangent? I just want to see what it looks like. Can you prove the Law of Tangent?
 

MarkFL

Administrator
Staff member
Feb 24, 2012
13,775
Can you state this law, preferably using \(\displaystyle \LaTeX\) for readability?
 

Country Boy

Well-known member
MHB Math Helper
Jan 30, 2018
426
MarkFL: I believe I stated it above but here it is in Latex:
$\frac{a- b}{a+ b}= \frac{tan(\frac{1}{2}(\alpha- \beta))}{tan(\frac{1}{2}(\alpha+ \beta)}$.

xyz- 1965: I wondered why there was no specific question in your post.
Someone deleted 3 or 4 threads I posted about 2 days ago. The reason given was NO WORK SHOWN. I can only show work if I know how to start the solution of the problem.
Seriously? If you are given homework where you do not even know how to start then you need to tell your teacher that! Your teacher needs to know to give you additional teaching.
 

Klaas van Aarsen

MHB Seeker
Staff member
Mar 5, 2012
8,736
Someone deleted 3 or 4 threads I posted about 2 days ago. The reason given was NO WORK SHOWN. I can only show work if I know how to start the solution of the problem.

All I needed was a simple hint or step to get me started. The questions did not need to be deleted. Again, there are questions in my precalculus textbook for which the author dooes not provide samples.
That would be me.
Please read the forum rules, which is what we enforce.

The relevant rule is:
Show some effort. If you want help with a question we expect you to show some effort. Effort might include showing your work, learning how to typeset equations using $\LaTeX$, making your question clearer, titling threads effectively and posting in the appropriate subforum, making a genuine attempt to understand the given help before asking for more help, and learning from previously asked questions. Moderators reserve the right to close threads in cases where the member is not making a genuine effort (particularly if the member is flooding the forums with multiple questions of the same type). You also should remember that all contributors to MHB are unpaid volunteers and are under no obligation to answer a question.
 
Last edited:

MarkFL

Administrator
Staff member
Feb 24, 2012
13,775
MarkFL: I believe I stated it above but here it is in Latex:
$\frac{a- b}{a+ b}= \frac{tan(\frac{1}{2}(\alpha- \beta))}{tan(\frac{1}{2}(\alpha+ \beta)}$.
I somehow missed that...I'm trying to encourage the OP to use LaTeX and so my post wasn't meant to address your post although I can see it looked that way.
 
  • Thread starter
  • Banned
  • #8

xyz_1965

Member
Jul 26, 2020
81
Can you state this law, preferably using \(\displaystyle \LaTeX\) for readability?
Yo Mark,

How is LaTex done? I have no idea.
 
  • Thread starter
  • Banned
  • #9

xyz_1965

Member
Jul 26, 2020
81
MarkFL: I believe I stated it above but here it is in Latex:
$\frac{a- b}{a+ b}= \frac{tan(\frac{1}{2}(\alpha- \beta))}{tan(\frac{1}{2}(\alpha+ \beta)}$.

xyz- 1965: I wondered why there was no specific question in your post.

Seriously? If you are given homework where you do not even know how to start then you need to tell your teacher that! Your teacher needs to know to give you additional teaching.
1. I am 55 not 15 in high school.

2. What? Don't believe me? Ask MarkFL. He knows more about me than everyone here.
 

xyz_1965

Member
Jul 26, 2020
81
I somehow missed that...I'm trying to encourage the OP to use LaTeX and so my post wasn't meant to address your post although I can see it looked that way.
Why are you attacking me? I told you millions of times that I do not know how to use Latex.
 

MarkFL

Administrator
Staff member
Feb 24, 2012
13,775

xyz_1965

Member
Jul 26, 2020
81

MarkFL

Administrator
Staff member
Feb 24, 2012
13,775
When I joined my first math help forum, I had never heard of LaTeX but by the time I had made 200 posts I knew it was something I had to learn if I was going to continue posting. In my case I was posting help but I think this applies to anyone who is going to participate on a math help forum for any length of time. You've been posting for longer than I have...likely tens of thousands of posts...and during .much of that time I have been trying to get you to learn it. You have resisted the entire time. I learned by looking at the posts of others like many others have done. You just don't want to do it. I don't know why.
 

xyz_1965

Member
Jul 26, 2020
81
When I joined my first math help forum, I had never heard of LaTeX but by the time I had made 200 posts I knew it was something I had to learn if I was going to continue posting. In my case I was posting help but I think this applies to anyone who is going to participate on a math help forum for any length of time. You've been posting for longer than I have...likely tens of thousands of posts...and during .much of that time I have been trying to get you to learn it. You have resisted the entire time. I learned by looking at the posts of others like many others have done. You just don't want to do it. I don't know why.
Ok. Can you check my recent posts to see if it is correct?
 

jonah

New member
Feb 21, 2015
9
Beer soaked ramblings follow.
I agree that the Law of Tangent is not needed if the other two solve the problem. Be that as it may, it looks interesting. Can you solve a problem using the Law of Tangent? I just want to see what it looks like.
If the next chapter in your personal studies is the Law of Sines and Law of Cosines, how can you agree that the Tangent law is not needed.
PrecalculusWithUnit-CircleTrigonometry4e2006CohenLeeSkylar,page726
PrecalculusWithUnit-CircleTrigonometry4e2006CohenLeeSkylar,page726.jpg
TrigonometricDelights1998EliMaor,page152
TrigonometricDelights1998EliMaor,page152.jpg
Scaum'sOutlineOfTheory&ProblemsOfPlane&SphericalTrigonometry1954FrankAyres,Jr.,page105
Scaum'sOutlineOfTheory&ProblemsOfPlane&SphericalTrigonometry1954FrankAyres,Jr.,page105.jpg
Now that you've seen what it looks like using tables, would you actually care to have a go at it using your calculator? Ah yes, I forget. You're that passionate math hobbyist who keeps posting math problems but doesn't own a calculator. Or was that your other split personality harpazzo. It's getting hard to keep track of your split personalities.

At any rate, if you do finally get a calculator, you need but note that A + B + C = 180° and you're basically done. A bit of creative thinking and blind application of the Tangent law formula should satisfy your wandering curiosity.