- #1
MarkFL
Gold Member
MHB
- 13,288
- 12
Here is the question:
I have posted a link there to this thread so the OP can view my work.
What is the surface area of this torus?
Here are the dimensions:
R=13"
r=4"
I thought of it as just a cylinder with the length being 26(pi) and the diameter being 8. I just keep on getting different answers every time I try to solve this problem. I got 2052.88 in², but I don't think it is correct.
I have posted a link there to this thread so the OP can view my work.