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#### karush

##### Well-known member

$$\theta=\tan^{-1}\sqrt{3}$$

rewrite

$$\tan(\theta)=\sqrt{3}$$

using $\displaystyle\tan\theta = \frac{\sin\theta}{\cos\theta}$ then if $\displaystyle\theta = \frac{\pi}{3}$

$$\displaystyle\frac{\sin\theta}{\cos\theta}

=\frac{\frac{\sqrt{3}}{2}}{\frac{1}{2}}

=\sqrt{3}$$

ok I think this is a little awkward since it is observing the unit circle to see what will work

so was wondering if there is a more proper way.