Kirchhoff's Three Laws of Spectroscopy

In summary: At low pressures, the elastic collision rate is low enough that the molecule's emission lines are not broadened.In summary, Kirchhoff's Three Laws of Spectroscopy explain the behavior of light emitted by different sources. An incandescent solid, liquid, or gas under high pressure will emit a continuous spectrum due to pressure broadening. A hot gas under low pressure will emit a bright-line or emission-line spectrum, while a continuous spectrum source viewed through a cool, low-density gas produces an absorption-line spectrum. This phenomenon is caused by the interactions between atoms and molecules at different pressures, resulting in the smearing out of emission lines.
  • #1
omoplata
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Kirchhoff's Three Laws of Spectroscopy are as follows.

1. An incandescent solid, liquid, or gas under high pressure, emits a continuous spectrum.
2. A hot gas under low pressure emits a "bright-line" or emission-line spectrum.
3. A continuous spectrum source viewed through a cool, low-density gas produces an absorption-line spectrum.

http://en.wikipedia.org/wiki/Spectrum_analysis" is the Wikipedia article I took that from.

How does an incandescent solid, liquid or gas under high pressure NOT have an emission line spectrum? Doesn't each atom this material is made up of emit emission lines as an electron transition happens from a higher energy level to a lower energy level? And and atom with an electron at a lower energy level can absorb a photon of correct frequency and transition to a higher energy level, right? Do these two processes cancel each other out?

Let's take a sample of an incandescent solid. I can understand how the emission photons from atoms at the middle of the sample being absorbed as they travel outwards. But if an atom at the outer edge of the sample emits a photon outwards, that doesn't get absorbed, right? So, shouldn't there be at least very faint emission lines?

And I guess even photons emitted from the center of a gas clump that is diffused can travel out through the clump without hitting other atoms because there is enough spatial separation between the atoms?

And how is light that does NOT have the frequency of an emission line get emitted? Maybe a derivation of black body radiation will help me understand this, but is there a simple qualitative explanation?

Thanks.
 
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  • #2
omoplata said:
How does an incandescent solid, liquid or gas under high pressure NOT have an emission line spectrum? Doesn't each atom this material is made up of emit emission lines as an electron transition happens from a higher energy level to a lower energy level?
The relevant effect here is pressure broadening. At high pressure, the atoms/molecules get squeezed very close together. At these short distances, the atoms/molecules start to have strong interactions. These interactions end up shifting the energies/frequencies of the characteristic emission lines. When you average the effect of these interactions over time, you end up seeing a continuous spectrum which is the result of the emission lines being smeared out by intermolecular interactions. If you were to do spectroscopy at a very fast timescale on a single molecule in the high pressure gas, you would still observe discrete emission lines. The critical timescale here is the time it takes for two atoms/molecules to collide and move apart (the elastic collision rate), and this depends on the density of the gas.
 
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Related to Kirchhoff's Three Laws of Spectroscopy

1. What are Kirchhoff's Three Laws of Spectroscopy?

Kirchhoff's Three Laws of Spectroscopy are a set of rules that describe the behavior of light when it passes through a medium. They were proposed by German physicist Gustav Kirchhoff in the mid-19th century.

2. What is the first law of Kirchhoff's Three Laws of Spectroscopy?

The first law states that a solid object, when heated, will emit a continuous spectrum of light. This means that the light emitted will contain all the colors of the rainbow.

3. What is the second law of Kirchhoff's Three Laws of Spectroscopy?

The second law states that a hot, low-density gas will produce a bright line spectrum, with specific wavelengths of light being emitted. This is known as an emission spectrum.

4. What is the third law of Kirchhoff's Three Laws of Spectroscopy?

The third law states that a cool, low-density gas will absorb certain wavelengths of light, leaving dark lines in its spectrum. This is known as an absorption spectrum.

5. Why are Kirchhoff's Three Laws of Spectroscopy important?

Kirchhoff's Three Laws of Spectroscopy are important because they allow scientists to analyze the composition and properties of different substances by studying the light they emit or absorb. This has applications in fields such as astronomy, chemistry, and materials science.

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