But there is a problem. Can we answer this question in other words where this work energy theorem is not used?Clever Penguin said:Yes, this is completely correct. The change in kinetic energy is zero.
Since force is perpendicular to the velocity, it has no component along the direction of the velocity vector. This means the force can't change the magnitude of the velocity. Hence, it remains constant.Vavi Ask said:But there is a problem. Can we answer this question in other words where this work energy theorem is not used?
Thanks a lot sir.cnh1995 said:Since force is perpendicular to the velocity, it has no component along the direction of the velocity vector. This means the force can't change the magnitude of the velocity. Hence, it remains constant.
Kinetic energy is the energy an object possesses due to its motion. When the force acting on an object is perpendicular to its velocity, the object will move in a circular path and its kinetic energy will be constantly changing.
The formula for calculating kinetic energy is KE = 1/2 * m * v^2, where m is the mass of the object and v is its velocity. When the force is perpendicular to velocity, the velocity term in the formula will be constantly changing, resulting in a constantly changing kinetic energy.
When the force is perpendicular to velocity, the force and velocity are always at right angles to each other, which means that the force does no work on the object. Therefore, the kinetic energy of the object remains constant.
Yes, kinetic energy can be converted into other forms of energy, such as potential energy or thermal energy, even when the force is perpendicular to velocity. This conversion occurs when the object's motion is affected by other forces, such as friction or gravity.
One example is a satellite orbiting the Earth. The satellite is constantly moving in a circular path due to the combination of its velocity and the gravitational force acting on it. Another example is a roller coaster, where the cars are constantly moving in a circular path due to the force of the track pushing them up and the force of gravity pulling them down.