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Serendipitydo
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Homework Statement
A mass moves in a circular path that has a radius of 24.6cm on a horizontal frictionaless surface. If the centripetal force acting on the mass is 96.5N, what is the kinetic energy of the mass?
r=0.246m
Fc=96.5N
Homework Equations
He told us to use these and "play around with them":
Fc=mv2/r
Ek=0.5mv2
The Attempt at a Solution
I have not a clue as to how to even begin this one. Maybe use the idea that acceleration centripetal=force centripetal(minus mass)? So use:
ac=v2/r
96.5N=v2/0.246m
v2=392m/s
v=19.8m/s
Fc=mv2/r
96.5N(0.246m)=m(19.8m/s)2
m=0.0605kg
Ek=0.5mv2
Ek=0.5(0,0605kg)(392m^2/s^2)
Ek=11.9J
Or am I completely and irrevocably lost?