- #1
SuperGeek
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I am stuck on this rotational motion with pulley question. Any help would be appreciated.
A block M2=5kg hangs off a pulley with mass from a string with tension T2 over a table edge.
A cylinder M1=3kg on the horizontal table top is attached to the string on the other end of the pulley (there is friction between the cylinder and table).
The cylinder is allowed to roll while the block is allowed to fall.
I need to compute linear acceleration of the roller-pulley-block system. The problem I have is that I am not sure what to use as the horizontal force on the cylinder.
Forces on m2: M2g - T2 = M2a
Forces on pulley: T2-T1 = 1\2ma
Forces on m1: N - m1g = 0 (vertical axis)
T1 - f = m1a
Should f = (Inertia of center of mass \ R^2)(a) ?
Thanks in advance for any responses.
A block M2=5kg hangs off a pulley with mass from a string with tension T2 over a table edge.
A cylinder M1=3kg on the horizontal table top is attached to the string on the other end of the pulley (there is friction between the cylinder and table).
The cylinder is allowed to roll while the block is allowed to fall.
I need to compute linear acceleration of the roller-pulley-block system. The problem I have is that I am not sure what to use as the horizontal force on the cylinder.
Forces on m2: M2g - T2 = M2a
Forces on pulley: T2-T1 = 1\2ma
Forces on m1: N - m1g = 0 (vertical axis)
T1 - f = m1a
Should f = (Inertia of center of mass \ R^2)(a) ?
Thanks in advance for any responses.