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Just wondering, how did they get the part boxed in blue?
Thanks.
The informal explanation is that as the labelling is essentialy arbitary the probabilities are all the same.Thanks for that, I realised it too however how does one show that $P(X_j, X_i) = P(X_1, X_2) = P(X_1, X_5)$ and so on?
It isn't so obvious to me that $P(X_1, X_2) = P(X_1, X_5)$