I'v quistion on Quadratic Functions

The graph of a quadratic function is a parabola, which has a maximum or minimum value. To find this value, you need to identify the vertex of the parabola. The x-value of the vertex can be found using the formula x = -b/2a, where a is the coefficient of the x^2 term and b is the coefficient of the x term. Once you have the x-value of the vertex, you can plug it into the function to find the corresponding y-value, which will be the maximum value of the function. In this case, the maximum value is 9375, which can be found by plugging x = 125/12 into the function. Therefore, the maximum value of f to four
  • #1
megatronic
16
0

Homework Statement


Let f(x)= 125x-6x2 find the maximum value of f to four decimal places graphically


Homework Equations


(x)= 125x-6x2


The Attempt at a Solution


Homework Statement



attempt solution:

x=-b+[tex]\sqrt{}b2-4ac[/tex]/2a

x=-125+[tex]\sqrt{}1252-4(-6)(0)[/tex]/2a

x= 0/-12=0

x=-b-[tex]\sqrt{}b2-4ac[/tex]/2a

x=-b-[tex]\sqrt{}b2-4ac[/tex]/2a

x=(-125-125)/-12

x=-125/6


Homework Equations





The Attempt at a Solution



 
Last edited:
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  • #2
Do you know how to make graph for quadratic equations?
 
  • #3
and also show your attempt otherwise nobody will help you here because of the rules of PF
 
  • #4
snshusat161 said:
Do you know how to make graph for quadratic equations?

ya I know to make graph for quadratic
 
  • #5
Ok then, do you realize there is a symmetry of any parabola on either end of its max/min? So if you find the roots of the quadratic, what can you deduce about the coordinates of the max/min from that?
 
  • #6
megatronic said:

Homework Statement


Let f(x)= 125x-6x2 find the maximum value of f to four decimal places graphically


Homework Equations


(x)= 125x-6x2


The Attempt at a Solution


Homework Statement



attempt solution:

x=-b+[tex]\sqrt{}b2-4ac[/tex]/2a

x=-125+[tex]\sqrt{}1252-4(-6)(0)[/tex]/2a

x= 0/-12=0

x=-b-[tex]\sqrt{}b2-4ac[/tex]/2a

x=-b-[tex]\sqrt{}b2-4ac[/tex]/2a

x=(-125-125)/-12

x=-125/6

What you've done is attempt to find the x-intercepts, which is not at all what this problem is asking for. In addition, there is one intercept that you did not find, and the one you found is incorrect.
 
  • #7
Think what 'maximum' is. Note that maximum does not refer to an x value.

There is a formula to determine the maximum or minimum value of a parabola. Give it a hard think. It'll come to you.
 
  • #8
Angry Citizen said:
Think what 'maximum' is. Note that maximum does not refer to an x value.

There is a formula to determine the maximum or minimum value of a parabola. Give it a hard think. It'll come to you.
The OP is not supposed to use a formula. He/she is supposed to find the maximum by looking at a graph of the function.
 

Related to I'v quistion on Quadratic Functions

1. What is a quadratic function?

A quadratic function is a type of polynomial function with a degree of 2. It can be written in the form f(x) = ax^2 + bx + c, where a, b, and c are constants and x is the variable.

2. What is the graph of a quadratic function?

The graph of a quadratic function is a parabola, which is a U-shaped curve. The direction and shape of the parabola depend on the values of the coefficients a, b, and c.

3. How do you find the vertex of a quadratic function?

The vertex of a quadratic function can be found by using the formula x = -b/2a. This will give you the x-coordinate of the vertex. To find the y-coordinate, you can substitute the x-coordinate into the original function.

4. What is the quadratic formula?

The quadratic formula is a formula used to solve quadratic equations. It is written as x = (-b ± √(b^2-4ac)) / 2a. This formula can be used to find the x-intercepts of a quadratic function or to solve a quadratic equation when it is set equal to 0.

5. What is the discriminant of a quadratic function?

The discriminant of a quadratic function is the expression under the square root in the quadratic formula, b^2-4ac. It can be used to determine the nature of the solutions of a quadratic equation. If the discriminant is positive, there are two real solutions. If it is zero, there is one real solution. And if it is negative, there are no real solutions.

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