Isobaric process experiment with plastic tube and hot water

In summary, the conversation is about an experiment involving a long plastic tube filled with hot water. The tube is closed at one end and the volume of water is measured to determine its mass. However, the results are inconsistent as the water level in the tube changes when the temperature changes. The individual is trying to understand the reason behind this and is considering factors such as pressure and volume. It is suggested that the air pressure at the closed end of the tube may be causing the changes in water level. After further discussion and consideration of the length of the tube, it is concluded that the changes in water level are due to adjustments in air pressure.
  • #1
wg1337
11
0
Hi! I have this experiment, that keeps getting me frustrated. The experiment is simple:
We have hot water and a long plastic tube with one end closed. We simply measure how much water is in the tube and from that we get the water volume (water is in cylinder shape).
But there is something I don't understand: when water is hotter then there is less water in tube (about 1cm long cylinder). When the water is less hot, then thee is more water (about 3cm long cylinder).
I can figure that the air which is at the end of tube is giving too much pressure so the volume doesn't add up.

For example, if this is really a isobaric process, then pV = RTm/M (p = RTm/(VM) should be the same all the time, but the numbers aren't the same.

If we want to threat water as an ideal gas, then the mass shouldn't change (could simply say that m/M is 1 mol), but the mass changes, because if the water expands because of heat, then there should be more water volume, not less. So the water actually flows away, can't really threat it as an ideal gas.

What I'm missing here?
It is possible that experiment is supposed to fail, but then I need a good reason. I don't think the mass change reason is a good enough reason.

For example:
length of cylinder - 0.008m
Diameter of tube - 0.0037m
Temperature - 337 K
Volume - 0.86 * 10^-7 m^3
Mass - 1000*0.86 * 10^-7 = 0.86*10^-4 kg
Molmass - 1 * 10^-3 kg/mol
Pressure - p = R*T*m/(V*M) = 8.31*337*0.86*10^-4/(0.86*10^-7*10^-3) = 2.8 * 10^9 Pa
So basically I get that there is 10 000 atm pressure... very possible...
 
Last edited:
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  • #2
Let me make sure I'm understanding this. You're heating a cylinder of water with the top end open. You take a measure of the height of the water and then let it cool. You take another measure and the water level is higher?
 
  • #3
I put a long plastic tube in hot water container. The water flows a little bit inside the tube, but not much. But when the water cools down, there is more volume of water inside the small plastic tube.

I was thinking that I did something wrong, but everyone gets the same results.

I know that density of water isn't 1000 at all temperatures, but it changes from 900 to 1000. That doesn't change much, we could say that this is what is making small number changes.
 
  • #4
I'm still having trouble understanding the setup. Could you draw a diagram or two?
 
  • #5
http://s18.postimage.org/bj0mv9kfb/exper.png

Sorry, should have drawn it earlier.
That small water volume changes upwards when temperature drops.
Guess we can assume that there is air at the closed end and the air pressure pushes out water.

I guess the way it works is like this: Since the temperature rises, the air expands more and pushes out water. Pressure shouldn't change (theoretically) for the water, only the volume changes. But still, having trouble with those extra 0. I can change the length how I want, it stays the same with mass and each other crosses out. Only when I changed molmass to 1 kg/mol from 0.001 kg/mol then I get 28 atm. pressure, but still not right.

But p=RTm/(VM) can't be used here. m = Density*V, so p = RT*Density*V/(V*M), the V cross out, so basically pressure is only depended on temperature.

[EDIT]
I understood now.
I was missing the length of tube. I'm not supposed to look at water pressure, but at air pressure.
The water in tube works as a cork, but changes in order to maintain pressure.
 
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Related to Isobaric process experiment with plastic tube and hot water

1. What is an isobaric process?

An isobaric process is a type of thermodynamic process in which the pressure remains constant while other variables, such as volume and temperature, may change. This means that the system is allowed to exchange heat and work with its surroundings, but the pressure must remain the same.

2. How does the plastic tube affect the isobaric process experiment?

The plastic tube serves as a container for the hot water, allowing for easier observation and measurement of the system's variables. It also helps to maintain a constant pressure within the system, as the tube is able to expand or contract slightly without significantly affecting the overall pressure.

3. Why is hot water used in the isobaric process experiment?

Hot water is used because it allows for a better demonstration of the isobaric process. As the temperature of the water increases, its volume also increases, causing the pressure to remain constant. This can be observed by measuring the volume of the water in the plastic tube as it is heated.

4. What are the key variables to measure in an isobaric process experiment?

The key variables to measure in an isobaric process experiment are pressure, volume, and temperature. These variables will help to determine whether the process is truly isobaric and allow for the calculation of other important parameters, such as the heat and work exchanged.

5. What real-life applications does the isobaric process have?

The isobaric process is commonly seen in everyday life, such as in the operation of a pressure cooker, where the pressure is kept constant while the temperature and volume change. It is also used in chemical reactions and industrial processes, where maintaining a constant pressure is crucial for safety and efficiency.

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