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- Feb 14, 2012
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Given \(\displaystyle \alpha\) is a non-negative real number and for every real number \(\displaystyle x\), we have \(\displaystyle (x+1)^2\ge \alpha(\alpha+1)\).
Is \(\displaystyle x^2\ge \alpha(\alpha-1)\)?
Is \(\displaystyle x^2\ge \alpha(\alpha-1)\)?