- #1
LAHLH
- 409
- 1
Hi,
On p104 of Srednicki's QFT, he does an integral in closed form, equations 14.43 and 14.44. I just ran the calculations for this in Mathematica, and I get his answer exactly except for my constants [tex] c_1=4-\pi\sqrt{3} [/tex] and [tex] c_2=4-2\pi\sqrt{3} [/tex].
The mathematica code I used to generate this was:
Then collecting the terms in k^2 and m^2, you find the constants I posted above, rather than the very similar but different Srednicki ones.
It's not listed on his errata page if this is an error, perhaps I am missing something? just seems very close, to not be correct.
On p104 of Srednicki's QFT, he does an integral in closed form, equations 14.43 and 14.44. I just ran the calculations for this in Mathematica, and I get his answer exactly except for my constants [tex] c_1=4-\pi\sqrt{3} [/tex] and [tex] c_2=4-2\pi\sqrt{3} [/tex].
The mathematica code I used to generate this was:
In[3]:= d[x_] := x*(1 - x)*k^2 + m^2
In[4]:= d0[x_] := (1 - x*(1 - x))*m^2
In[5]:= p[x_] = (1/2)*a*d[x]*Log[d[x]/d0[x]]
Out[5]= 1/2 a (m^2 + k^2 (1 - x) x) Log[(m^2 + k^2 (1 - x) x)/(
m^2 (1 - (1 - x) x))]
In[12]:= Integrate[p[x], {x, 0, 1},
Assumptions -> {Element[m, Reals], Element[k, Reals], m > 0, k > 0}]
Out[12]= (1/(12 k Sqrt[
k^2 + 4 m^2]))a (k Sqrt[
k^2 + 4 m^2] (4 (k^2 + m^2) - Sqrt[3] (k^2 + 2 m^2) \[Pi]) +
2 (k^2 + 4 m^2)^2 ArcTanh[k/Sqrt[k^2 + 4 m^2]])
Then collecting the terms in k^2 and m^2, you find the constants I posted above, rather than the very similar but different Srednicki ones.
It's not listed on his errata page if this is an error, perhaps I am missing something? just seems very close, to not be correct.