- #1
Lucw
- 35
- 1
Hello.
Sorry for my English.
I have found on the net a solution of Newton equation. And I just want to have your view.
The speed between two mobiles moving towards each other is: (only with gravitation)
dx/dt = - square root (2.G.(m1+m2).(1/X0 -1/X))
Where X0 is the distance between the two mobiles when they are released without initial speed.
And X the distance where we measure the speed. (X0>X).
A solution is: (SR is square root)
t=SR (X0³/(2.G.(m1+m2))).(X/X0.SR(X0/X-1)+arctg(SR(X0/X-1)))
The author of the solution poses: u = SR(X0/X-1).
Thank you for your opinion.
Lucw
Sorry for my English.
I have found on the net a solution of Newton equation. And I just want to have your view.
The speed between two mobiles moving towards each other is: (only with gravitation)
dx/dt = - square root (2.G.(m1+m2).(1/X0 -1/X))
Where X0 is the distance between the two mobiles when they are released without initial speed.
And X the distance where we measure the speed. (X0>X).
A solution is: (SR is square root)
t=SR (X0³/(2.G.(m1+m2))).(X/X0.SR(X0/X-1)+arctg(SR(X0/X-1)))
The author of the solution poses: u = SR(X0/X-1).
Thank you for your opinion.
Lucw