Is the solution correct? (forces between 3 charged particles)

In summary: Without units, it's impossible to compare the magnitude of forces. In summary, the drawing does not correctly depict the vector nature of forces.
  • #1
PhysicsTeacher159
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2
Homework Statement
Three charges are arranged in a li ne with 2.5 cm between them, as shown in Figure 2.33. What is the force exerted on a Charge 2 by the other two charges?
Relevant Equations
Coulomb's law
Example2.7page66Physics10thgrade.png
 
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  • #2
Well it depends on what you mean by "total". If you define "total" to be the sum of the magnitudes, then it's fine. But that definition is not really helpful, for anything. It's certainly not how I would interpret it.

It's much more common for "total" to mean the vector sum, or equivalently if you write those vectors in terms of a basis, the sum of the components of a particular basis vector.

In that case, if you for instance let the ##\hat{x}## basis vector point to the right, the ##x##-component of the resultant force is going to be ##F_x = F_{12} - F_{32}##. This is now a useful quantity, which you can use to e.g. determine the instantaneous acceleration.
 
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  • #3
Thanks.
 
  • #4
Does the worked example come from an "official" book? I can't believe how the "author" ignores the vector nature of forces.
 
  • #5
PhysicsTeacher159 said:
Thanks.
To add to what @etotheipi said: if the forces ##F_{12}## and ##F_{32}## were equal and opposite, then the total force on ##q_2## would definitely be zero. You definitely need a minus sign.

Note that the electric field is what determines the force on ##q_2##. There is no sense in which you can add the magnitude of electric fields - they must be added vectorially.
 
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  • #6
I am reminded of the chapter from "Surely Your Joking..." where Prof Feynman is approving high school texts for the school board and one problem asks for the sum of the temperatures of four stars. Equivalently cringeworthy calculation.
 
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  • #7
The directions of the arrows representing F12 and F32 are correctly drawn but with their tips at the charge instead of their tails. Grasping at straws, I can hypothesize how one might look at the drawing and erroneously conclude that since one charge "squeezes" q2 from the left and the other squeezes from the right, charge q2 is squozen from both sides with a "total" force that is the sum of the two forces because it should be a harder squeeze than if either force alone acted on the charge. Something like that but still indicative of poor understanding of what a net force and Newton's 2nd are all about.

I also lament the lack of units in the answer.
 

Related to Is the solution correct? (forces between 3 charged particles)

1. What are the forces between 3 charged particles?

The forces between 3 charged particles are known as Coulomb's law forces. These forces depend on the magnitude and sign of the charges and the distance between the particles.

2. How do you determine if the solution for the forces between 3 charged particles is correct?

The solution for the forces between 3 charged particles can be determined by using Coulomb's law equation, which takes into account the charges and distance between the particles. The calculated forces should match the expected values based on the given charges and distance.

3. Can the solution for the forces between 3 charged particles be incorrect?

Yes, the solution for the forces between 3 charged particles can be incorrect if there are errors in the calculations or if the charges and distances are not accurately measured. It is important to double check the calculations and inputs to ensure an accurate solution.

4. Are there any other factors that can affect the solution for the forces between 3 charged particles?

Yes, in addition to the charges and distance, the medium between the particles can also affect the solution for the forces. For example, if the particles are in a medium with a high dielectric constant, the forces between them will be weaker compared to a medium with a low dielectric constant.

5. How can the solution for the forces between 3 charged particles be applied in real-world situations?

The solution for the forces between 3 charged particles can be applied in various real-world situations, such as studying the behavior of particles in an electric field, designing electrical circuits, and understanding the forces between atoms and molecules. It is a fundamental concept in the study of electromagnetism and has many practical applications in technology and engineering.

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