Is the Derivation of Ekman Transport Correct with These Assumptions?

In summary, the professor showed that the Ekman transport equation can be derived by assuming constant density, stationarity, and no horizontal pressure or velocity gradients, as well as no vertical velocity. However, there was a mistake in using the ordinary derivative instead of the partial derivative in the derivation.
  • #1
ATY
34
1
Hey guys,
I need your help.
We tried to derive the ekman transport in a lecture. The assumptions we made are
1. constant density
2. stationarity
3. no horizontal pressure gradient and no horizontal velocity gradient
4. no vertical velocity.
So this is what the professor showed us:
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f87c495a7b.png

But is this correct ? I thought that from stationarity we get [itex]\frac{\partial}{\partial t}=0[/itex] instead of [itex]\frac{d}{dt} = 0[/itex].
I would still get to the correct result using
[itex]\frac{\partial u}{\partial x}=\frac{\partial v}{\partial x}=\frac{\partial v}{\partial y}=\frac{\partial v}{\partial x}=0[/itex] and [itex]w=0[/itex] in order to eliminate all terms on the left side of the equation.
Can somebody help me ?
 
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  • #2
Yes, you are correct. The professor should have used the partial derivative in place of the ordinary (total) derivative. Using the assumptions you listed, you can indeed derive the Ekman transport equation by setting all of the derivatives equal to zero. This can be done by setting the horizontal pressure gradient and horizontal velocity gradient to zero, and setting the vertical velocity to zero.
 

Related to Is the Derivation of Ekman Transport Correct with These Assumptions?

1. What is the Derivation of Ekman Transport?

The Derivation of Ekman Transport is a mathematical model used to explain the movement of ocean currents caused by wind stress. It was developed by Swedish oceanographer Vagn Walfrid Ekman in 1902.

2. How does Ekman Transport affect ocean currents?

Ekman Transport is caused by the Coriolis effect, which is the deflection of objects moving along the surface of the Earth due to its rotation. This deflection causes ocean currents to move at a 90 degree angle to the direction of the wind.

3. What factors influence Ekman Transport?

The strength and direction of the wind, as well as the Earth's rotation and the density of the water, all play a role in determining the magnitude and direction of Ekman Transport.

4. How is Ekman Transport calculated?

The formula for Ekman Transport is T = (1/ρ)fV, where T is the transport, ρ is the density of the water, f is the Coriolis parameter, and V is the wind velocity. This formula takes into account the factors that influence Ekman Transport.

5. What are the practical applications of understanding Ekman Transport?

Understanding Ekman Transport is crucial for predicting ocean currents and their impact on marine life, shipping routes, and coastal erosion. It is also important for studying climate patterns and weather forecasting.

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