Is my mass calculation method correct?

In summary, the mass of the larger object will be approximately 1.25 billion kilograms, assuming the density remains constant.
  • #1
5P@N
58
3

Homework Statement


I have an object of a known mass, and known dimension along one axis (length).
Mass: 10 kg
Length: 2 meters

I wish to calculate what the mass of an object that is similarly constituted and shaped will be if it has a greatly expanded length of: 1,000 meters.

I am seeking to know what the mass of this larger object will be.

Homework Equations


Volume = Length * Width * Height

Conversion factor = larger object / smaller object

{ (conversion factor)^3 } * mass of smaller object = mass of larger object
(The conversion factor is cubed so as to account for all 3 volumetric dimensions of expansion)

The Attempt at a Solution


1,000 m / 2 m = 500
500 = conversion factor
(500)^3 = 125,000,000

This 125 million is then multiplied by the original mass of 10 kg, to get an answer of: 1 billion, 250 million kg.

Does anybody see a problem with my result and/or logic? Reply if you do.
 
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  • #2
5P@N said:

Homework Statement


I have an object of a known mass, and known dimension along one axis (length).
Mass: 10 kg
Length: 2 meters

I wish to calculate what the mass of an object that is similarly constituted and shaped will be if it has a greatly expanded length of: 1,000 meters.

I am seeking to know what the mass of this larger object will be.

Homework Equations


Volume = Length * Width * Height

Conversion factor = larger object / smaller object

{ (conversion factor)^3 } * mass of smaller object = mass of larger object
(The conversion factor is cubed so as to account for all 3 volumetric dimensions of expansion)

The Attempt at a Solution


1,000 m / 2 m = 500
500 = conversion factor
(500)^3 = 125,000,000

This 125 million is then multiplied by the original mass of 10 kg, to get an answer of: 1 billion, 250 million kg.

Does anybody see a problem with my result and/or logic? Reply if you do.
Looks fine to me.
 
  • #3
You want to make it 500 times longer, wider, and thicker, so it will have a volume that's ##(500)^3## times bigger. Assuming you keep the density of the object the same, the mass will increase by the same factor:$$10 \ \mathrm{kg} \times (500)^3=1.25 \times 10^9 \ \mathrm {kg}$$
 

Related to Is my mass calculation method correct?

1. How do I know if my mass calculation method is accurate?

The accuracy of your mass calculation method can be determined by comparing your results to known values or using a validated method. You can also repeat your calculations multiple times to ensure consistent results.

2. What are the common sources of error in mass calculations?

Some common sources of error in mass calculations include incorrect measurement units, faulty equipment, human error, and incomplete data.

3. Can I use any mass calculation method for any type of sample?

It is important to use a mass calculation method that is appropriate for the type of sample you are working with. Different samples may require different equations or techniques.

4. How can I improve the accuracy of my mass calculations?

To improve the accuracy of your mass calculations, you can use precise measuring equipment, carefully record data, and use multiple methods to cross-check your results.

5. Should I include uncertainties in my mass calculations?

Yes, it is important to include uncertainties in your mass calculations to accurately represent the precision of your measurements. You can calculate uncertainties using statistical methods or by using the precision of your equipment.

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