- #1
kieran89
- 2
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1. Hello. I am doing a practical assignment which involves a pully system with different masses on each side attached to a string. I have figured out acceleration via a = 2x/t^2 and then Force applied by F = (.42-.38)*0.286 which gives me 0.011N. However when I graph the final solution (I have changed the weight difference (.430 and .390) as a Force (yaxis) and Acceleration (xaxis) graph it is basically saying that at 0N applied i am getting 0.18ms-2!.
2. x=1.48m
Am i calculating the applied force correctly?
3. m1 (kg) m2 (kg) t (s) a (m s-2) aaverage (m s-2) Fapp (N)
Trial 1 0.420 0.380 3.21 0.287
Trial 2 0.420 0.380 3.25 0.280
Trial 3 0.420 0.380 3.15 0.298 0.286 0.011
Trial 4 0.420 0.380 3.17 0.295
Trial 5 0.420 0.380 3.22 0.285
2. x=1.48m
Am i calculating the applied force correctly?
3. m1 (kg) m2 (kg) t (s) a (m s-2) aaverage (m s-2) Fapp (N)
Trial 1 0.420 0.380 3.21 0.287
Trial 2 0.420 0.380 3.25 0.280
Trial 3 0.420 0.380 3.15 0.298 0.286 0.011
Trial 4 0.420 0.380 3.17 0.295
Trial 5 0.420 0.380 3.22 0.285
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