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mpekatsoula
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Well i found this sentence: "If the number of even bits minus the number of odd bits is a multiple of 3 (e.g. -3,0,3,6, etc) then the number is divisible by three." Can anyone tell me the proof of this?
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Binary divisibility by 3 is a property of a binary number, meaning that the sum of its digits is divisible by 3. This is similar to the concept of divisibility by 3 in our base-10 number system, where the sum of the digits must be divisible by 3 for the number to be divisible by 3.
To determine if a binary number is divisible by 3, you can add up all of its digits and check if the sum is divisible by 3. If the sum is divisible by 3, then the binary number is also divisible by 3.
No, a binary number with a decimal point cannot be divisible by 3. This is because the decimal point represents a fractional value, and it does not contribute to the sum of the digits in the binary number.
Yes, there are patterns in binary divisibility by 3. For example, every other binary number is divisible by 3, starting with 3 (11 in binary), 6 (110 in binary), 9 (1001 in binary), and so on. Additionally, a binary number is divisible by 3 if the number of 1s in its binary representation is divisible by 3.
Binary divisibility by 3 is often used in error detection and correction algorithms. By adding a parity bit (a 1 or 0) to a binary number to make it divisible by 3, errors can be detected and corrected if the sum of the digits is no longer divisible by 3.