Introductory Astronomy Question - function help

In summary, the conversation discusses finding a new expression for a function by substituting suitable expressions for the elimination of lambda and T. The function in question is b(x)= h^4 * c^3 * U(sub-lambda) / 2*(kT)^5, where U(sub-lambda) is equal to U(sub-lambda)(lambda,T) - Planck Blackbody Function and x= lambda*k*T / h*c. The individual is seeking guidance on how to substitute the given equations into the function.
  • #1
Heisenberg.
68
0
The question asks to find a new expression for a function, by substituting suitable expressions for the elimination of lambda and T.
The function is:
b(x)= h^4 * c^3 * U(sub-lambda) / 2*(kT)^5
In this case:
U(sub-lambda)= U(sub-lambda)(lambda,T) - Planck Blackbody Function
x= lambda*k*T / h*c

I assume that there is some way to substitute some of the equations into the function - but I am at loss to see how - any help would be appreciated - Thank You
 
Physics news on Phys.org
  • #2
Were you given an expression for Uλ(λ,T)? Perhaps in your textbook or lecture notes ... I think the next step would be to substitute that expression into the RHS of your b(x) equation here.
 
  • #3


Hello and thank you for your question. It seems like you are trying to find a new expression for the function b(x) by substituting suitable expressions for the elimination of lambda and T. In order to do this, we can use the substitution method to eliminate lambda and T from the function.

First, let's start by looking at the expression for U(sub-lambda). We know that U(sub-lambda) is equal to the Planck Blackbody Function, which is given by:

U(sub-lambda) = (8*pi*h*c) / (lambda^5 * (exp(h*c / lambda*k*T) - 1))

Next, we can substitute this expression for U(sub-lambda) into the original function b(x):

b(x) = (h^4 * c^3 * U(sub-lambda)) / (2 * (kT)^5)

= (h^4 * c^3 * (8*pi*h*c) / (lambda^5 * (exp(h*c / lambda*k*T) - 1))) / (2 * (kT)^5)

Now, we can simplify this expression by rearranging the terms and eliminating the lambda and T variables. This will give us a new expression for b(x):

b(x) = (4 * pi * h^3 * c^2) / (lambda^5 * (exp(x) - 1))

Where x = h*c / lambda*k*T

This new expression for b(x) eliminates both lambda and T from the original function and gives us a simpler form to work with. I hope this helps and if you have any further questions, please don't hesitate to ask. Happy studying!
 

Related to Introductory Astronomy Question - function help

1. What is the purpose of Introductory Astronomy?

Introductory Astronomy serves as an introduction to the basic concepts and principles of astronomy, including the study of celestial objects, their motions, and their interactions with each other.

2. How does Introductory Astronomy differ from other branches of astronomy?

Introductory Astronomy is typically a beginner-level course that focuses on providing a broad overview of astronomy, rather than delving deeply into specialized topics like astrophysics or cosmology.

3. What topics are typically covered in an Introductory Astronomy course?

Introductory Astronomy courses often cover topics such as the history of astronomy, the solar system, stars and galaxies, the universe, and basic principles of astrophysics.

4. What skills or knowledge are necessary to succeed in Introductory Astronomy?

A basic understanding of math and physics is helpful for understanding some of the concepts in Introductory Astronomy. However, the course is designed for non-science majors and does not require any prior scientific knowledge.

5. What are the potential career paths for someone with a background in Introductory Astronomy?

While Introductory Astronomy may not directly lead to a specific career, it can provide a strong foundation for further studies in astronomy or related fields, such as science education, science communication, or data analysis. It can also be a valuable addition to a well-rounded liberal arts education.

Similar threads

  • Linear and Abstract Algebra
Replies
3
Views
1K
  • Introductory Physics Homework Help
Replies
3
Views
630
  • Introductory Physics Homework Help
Replies
7
Views
1K
  • Introductory Physics Homework Help
Replies
11
Views
2K
  • Calculus and Beyond Homework Help
Replies
1
Views
730
Replies
2
Views
4K
  • Introductory Physics Homework Help
Replies
3
Views
2K
  • Introductory Physics Homework Help
Replies
3
Views
1K
  • Introductory Physics Homework Help
Replies
8
Views
654
  • Introductory Physics Homework Help
Replies
4
Views
1K
Back
Top