Interferometer Experiment: Rules for Adding Half Wavelength

In summary: The optical path length is the actual physical distance traversed by light multiplied by the index of the material it's in. So if you go through a medium of index n, the light travels n d where d is the actual physical distance, so things like the thickness of the glass, or the width of an air gap, are multiplied by n.In summary, when the index of refraction on the material "after" the surface is greater than the index of refraction "before" the surface, a half-wavelength is added to the reflected wave. This does not happen in transmission. If the reflector is not perfect and the splitter is not 50/50, the portion of the wave that is reflected will still have a half
  • #1
KFC
488
4
I am reading a scientific essay about a experiment with interferometer. They use so called 50/50 beam splitter and perfect reflector. Well they have the input wave be the plane wave [tex]exp(ikx)[/tex], what interesting is: whenever the wave reflected by the splitter or perfect reflector, it add half of the wavelength to the wave, but if the wave was transmitted through the splitter, no wavelength was added to it. It is so confusing. What's the rule behind this?

1) When will the half wavelength being added to the wave? Only happen in reflection?
2) If the reflector is not perfect and the splitter is not 50/50 (30/70 or 80/20), will it still be a half-wavelength added? or any other portion of wavelength being added?
 
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  • #2
KFC said:
1) When will the half wavelength being added to the wave? Only happen in reflection?

Only in reflection, and only when the index of refraction (n) of the material "after" the surface is greater than the index of refraction "before" the surface. E.g. when the light is traveling in air and hits a glass surface, the reflected wave has the half-wavelength added, but when the light is traveling in glass and hits a surface with air on the other side, this does not happen.

2) If the reflector is not perfect and the splitter is not 50/50 (30/70 or 80/20), will it still be a half-wavelength added? or any other portion of wavelength being added?

The portion of the wave that is reflected has the half-wavelength added (provided the index of refraction on the two sides is as described above), the transmitted portion of the wave does not (regardless of how the index of refraction goes).
 
  • #3
KFC said:
I am reading a scientific essay about a experiment with interferometer. They use so called 50/50 beam splitter and perfect reflector. Well they have the input wave be the plane wave [tex]exp(ikx)[/tex], what interesting is: whenever the wave reflected by the splitter or perfect reflector, it add half of the wavelength to the wave, but if the wave was transmitted through the splitter, no wavelength was added to it. It is so confusing. What's the rule behind this?

1) When will the half wavelength being added to the wave? Only happen in reflection?
2) If the reflector is not perfect and the splitter is not 50/50 (30/70 or 80/20), will it still be a half-wavelength added? or any other portion of wavelength being added?

It's not exactly adding a half-wavelength, it's more correctly a reversal of the wavefront- equivalently, the phase is advanced 1/2 of a period when reflections occur from some interfaces, while the phase is not advanced when reflection soccur from other inteerfaces:

http://www.kettering.edu/~drussell/Demos/reflect/reflect.html
 
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  • #4
Yeah, some books handle it as a phase shift of [itex]\pi[/itex] radians (which is what it "really" is), and some books handle it by adding [itex]\lambda / 2[/itex] to the optical path length, which is equivalent.
 

Related to Interferometer Experiment: Rules for Adding Half Wavelength

What is an interferometer experiment?

An interferometer experiment is an optical instrument used to measure the properties of waves, such as light or sound. It works by splitting a beam of light or sound into two parts and then recombining them to create interference patterns that can reveal information about the waves.

How does an interferometer experiment work?

An interferometer experiment works by using a beam splitter to split a beam of light or sound into two parts. One part travels through a reference path and the other through a sample path. The two parts are then recombined and the resulting interference pattern is measured to determine the properties of the waves.

What are the rules for adding half wavelength in an interferometer experiment?

The rules for adding half wavelength in an interferometer experiment are:1. When the two parts of the beam are recombined, if the waves are in phase (crest to crest or trough to trough), they will reinforce each other and create a bright interference pattern.2. If the waves are out of phase (crest to trough), they will cancel each other out and create a dark interference pattern.3. When adding half a wavelength to one of the paths, the waves will be shifted by half a wavelength, causing them to either reinforce or cancel each other out.4. By adjusting the path length of one of the beams by half a wavelength, the interference pattern can be manipulated to reveal more information about the waves.

What are the applications of interferometer experiments?

Interferometer experiments have a wide range of applications, including:1. Measuring small displacements, such as the motion of microscopic objects.2. Measuring the refractive index and other properties of materials.3. Testing the flatness and smoothness of surfaces.4. Creating high-resolution images in astronomy.5. Measuring the speed and direction of moving objects, such as in radar technology.

What are the limitations of interferometer experiments?

While interferometer experiments have many applications, they also have some limitations, including:1. They require a stable environment and precise alignment to obtain accurate results.2. The resolution of an interferometer is limited by the wavelength of the light or sound being used.3. They are limited to measuring properties of waves, and cannot be used for other types of measurements.4. They can be affected by external factors such as vibrations or temperature changes.5. They can be expensive and complex to set up and use.

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