- #1
thecourtholio
- 19
- 1
Homework Statement
Find the interaction energy ( ##\epsilon_0 \int \vec{E_1}\cdot\vec{E_2}d\tau##) for two point charges, ##q_1## and ##q_2##, a distance ##a## apart. [Hint: put ##q_1## at the origin and ##q_2## on the z axis; use spherical coordinates, and do the ##r## integral first.]
Homework Equations
Interaction Energy is given by: $$ \epsilon_0 \int \vec{E_1}\cdot\vec{E_2}d\tau$$
where ##d\tau## is the volume element, which in spherical coordinates is ##rsin\theta dr d\theta d\phi##
The Attempt at a Solution
So I know that $$\vec{E_1} = \frac{q_1}{4\pi\epsilon_0 r_1^2}\hat{r_1}$$ and $$\vec{E_2} = \frac{q_2}{4\pi\epsilon_0 r_2^2}\hat{r_2}$$
So the dot product then is $$\vec{E_1}\cdot\vec{E_2} = \frac{1}{(4\pi\epsilon_0)^2} \frac{q_1}{r_1^2}\frac{q_2}{r_2^2}\hat{r_1}\cdot\hat{r_2}$$
But since ##\hat{r}=\frac{\vec{r}}{|r|}##, this can be written as $$\vec{E_1}\cdot\vec{E_2} = \frac{1}{(4\pi\epsilon_0)^2} \frac{q_1}{r_1^3}\frac{q_2}{r_2^3}\vec{r_1}\cdot\vec{r_2}$$
But I also know that the dot product can be expressed as ##\vec{E_1}\cdot\vec{E_2}=|E_1||E_2|cos\alpha## where ##\alpha## is the angle between them. So then ##\vec{E_1}\cdot\vec{E_2}## can also be written as $$\vec{E_1}\cdot\vec{E_2} = \frac{1}{(4\pi\epsilon_0)^2} \frac{q_1}{r_1^2}\frac{q_2}{r_2^2}cos\alpha$$
So now, I'm not sure which version would be better to use because I don't know how to relate ##\alpha## to ##\theta## in the last version and for the first two versions, I'm not really sure how to define the position vectors because if ##q_1## is at the origin and ##q_2## is on the z axis then ##\vec{r_1}\cdot\vec{r_2}=0## and then the whole thing would just be 0 right? And when I go to integrate over ##r##, which ##r## is used in the volume element since there is ##r_1## and ##r_2##? I feel like there is some geometry that I am missing. And is the integration just the usual ##0\leq r \leq \infty##, ##0\leq\theta\leq \pi##, ##0\leq\phi\leq 2\pi##? Any help would be awesome!