- Thread starter
- #1
Hi Bincy,Hii Everyone,
\(\displaystyle \int\frac{1}{x^{r}-1}dx
\) where r is a real no. greater than 1
regards,
Bincy
... and if $|x|>1$ then You can set $\displaystyle t=\frac{1}{x}$ and the function to be integrated becomes...If $|x|<1$ then is...
$\displaystyle \frac{1}{x^{r}-1} = - \sum_{n=0}^{\infty} x^{n\ r}$ (1)
... and You can integrate the expression (1) 'term by term'...
chisigma is just using the sum of an infinite geometric series:Can you plz explain me the source of these formula?