- Thread starter
- #1

- Thread starter Yankel
- Start date

- Thread starter
- #1

- Jan 31, 2012

- 253

- Thread starter
- #3

- Jan 31, 2012

- 253

$$\frac{x^{2}}{x^{2}-1} = 1 + \frac{1}{x^{2}-1} = 1 + \frac{1}{2} \Big( \frac{1}{x-1} - \frac{1}{x+1} \Big)$$

- Admin
- #5

- Jan 26, 2012

- 4,193

Actually, that's exactly what we do prefer here at MHB. You can ask two questions per thread, but please do not start a new question in the middle of an existing thread.I want to ask for help with one more integral, seems a waste to start a new thread,

Thanks!

- Feb 9, 2012

- 118

\(\displaystyle \ln(x^2-1)=\ln(x+1)+\ln(x-1).\)I want to ask for help with one more integral, seems a waste to start a new thread, I need this:

\[ln(x^{2}-1)\]

I tried using integration in parts and got stuck with the integral of:

\[\frac{2x^{2}}{x^{2}-1}\]

Thanks !