- Thread starter
- #1
Actually, that's exactly what we do prefer here at MHB. You can ask two questions per thread, but please do not start a new question in the middle of an existing thread.I want to ask for help with one more integral, seems a waste to start a new thread,
\(\displaystyle \ln(x^2-1)=\ln(x+1)+\ln(x-1).\)I want to ask for help with one more integral, seems a waste to start a new thread, I need this:
\[ln(x^{2}-1)\]
I tried using integration in parts and got stuck with the integral of:
\[\frac{2x^{2}}{x^{2}-1}\]
Thanks !