- #1
silence
i can solve x^x but adding this new x just confuses me any help will do, X^x^x
djuiceholder said:but can you do (x^x)^x ??
it seems impossible
The derivative of x^x^x is a complex function that involves multiple applications of the chain rule and logarithmic differentiation. The result is x^x^x * (1 + ln(x) + ln(ln(x))).
To find the derivative of x^x^x, you need to use logarithmic differentiation and the chain rule. First, take the natural logarithm of both sides to get ln(y) = x^x * ln(x). Then, use the product rule and chain rule to simplify and solve for y'. Finally, replace y with x^x^x to get the final derivative.
The graph of the derivative of x^x^x is a non-linear function with a steep incline at x=1 and a horizontal asymptote at x=0. It also has a critical point at x=1, where the derivative is undefined.
No, the derivative of x^x^x is not continuous. It has a discontinuity at x=0, where the derivative is undefined.
The value of x=1 is a critical point in the derivative of x^x^x, where the derivative is undefined. This means that the original function, x^x^x, has a point of inflection at x=1, where the concavity changes from upward to downward.