- Thread starter
- #1
paulmdrdo
Active member
- May 13, 2013
- 386
I have no idea how to solve these. please help.
∫(sinx/1+sinx)dx
∫(sin^2x cos^2x)dx
∫(sinx/1+sinx)dx
∫(sin^2x cos^2x)dx
You [OP] can also reach this result by using the double angle identity for cos if you're unfamiliar with the power reduction identity. See spoiler for derivation.Then try the power reduction identity for sine \(\displaystyle \sin^2(\theta)=\frac{1-\cos(2\theta)}{2}\).