- Thread starter
- #1

#### paulmdrdo

##### Active member

- May 13, 2013

- 386

1. ∫(dx/x

^{2}-x+2)

completing the square of the denominator i have,

∫[dx/(x-1)

^{2}+1

^{2}]

a=1, u=x-1; du=dx

∫(du/a

^{2}+u

^{2})

1/1*tan

^{-1}x-1/1 + c = tan

^{-1}x-1 + C -->> final answer

2. ∫[dx/(15+2x-x

^{2})

^{1/2}]

∫[dx/(14-(x-1)

^{2})

^{1/2}]

∫{dx/([(14)

^{1/2}]

^{2}-(x-1)

^{2})}

a = (14)

^{1/2}; u = x-1; du = dx

= 1/(14)

^{1/2}*sin

^{-1}x-1/(14)

^{1/2}+ C --->>final answer

and P.S how to use that font that you are using?