- Thread starter
- #1
bergausstein
Active member
- Jul 30, 2013
- 191
any hints on how to work out this problems.
$\displaystyle\int\frac{dx}{(1-sinx)^2}$
$\displaystyle\int\sin x\sin2x\sin3x dx$
thanks!
$\displaystyle\int\frac{dx}{(1-sinx)^2}$
$\displaystyle\int\sin x\sin2x\sin3x dx$
thanks!