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I am working on this integral.

\[\int ln(3x+1)dx\]

I choose u=ln(3x+1) and v'=1. It got me to:

\[x\cdot ln(3x+1)-\int \frac{3x}{3x+1}dx\]

What should I do from here ? Some substitution ? The x up there bothers me...no easier way ? Thank!

I also need to solve:

\[\int (ln(x))^{2}dx\]

any hints ?

P.S must use parts on this one